Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:40Z
2ψ² + 5ψ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
276K
det| 9 4 ; 1 10 | = 86
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∑_{k=1}^{n} k = n(n+1)/2
191K
∇²z = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
1K
det| 5 6 ; 7 6 | = -12
153K
N₂ + 3H₂ ⇌ 2NH₃
det| 5 3 ; 7 6 | = 9
473K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
8t² + 2t + 3 = 0