Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:27Z
∇²α = 0
det| 7 4 ; 4 8 | = 40
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6φ² + 8φ + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∂φ/∂φ = 1φ
\oint_C \vec{F}\cdot d\vec{r} = 0
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det| 4 8 ; 1 5 | = 12
∑_{k=1}^{n} k = n(n+1)/2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
7φ² + 2φ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O