Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:14Z
11t² + 7t + 4 = 0
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
201K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
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∫₀^∞ e^(-t²) dt = √π / 2
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\lim_{t\to 0} \frac{\sin t}{t} = 1
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