Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:02Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 11 4 ; 5 12 | = 112
479K
3β² + 6β + 2 = 0
det| 3 6 ; 0 4 | = 12
276K
det| 1 1 ; 5 2 | = -3
129K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
1K
1x² + 5x + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
338K
∇²ψ = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
3φ² + 8φ + 6 = 0