Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:08Z
11t² + 7t + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
326K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
366K
det| 5 6 ; 2 6 | = 18
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 9 4 ; 1 10 | = 86
176K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
263K
det| 10 1 ; 4 11 | = 106
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
iħ ∂ψ/∂t = Ĥψ