Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 06:41Z
det| 4 5 ; 4 5 | = 0
∑_{k=1}^{n} k = n(n+1)/2
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N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
276K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
∑_{k=1}^{n} k = n(n+1)/2
390K
det| 10 9 ; 0 11 | = 110
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
473K
det| 5 2 ; 3 6 | = 24
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