Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 06:44Z
det| 4 5 ; 4 5 | = 0
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
276K
∑_{k=1}^{n} k = n(n+1)/2
129K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
F = G m₁m₂ / r²
CH₄ + 2O₂ → CO₂ + 2H₂O
1K
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
473K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
e^{i\pi} + 1 = 0
F = G m₁m₂ / r²
F = ma