Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:17Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
276K
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
191K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
338K
\lim_{t\to 0} \frac{\sin t}{t} = 1
188K