Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:51Z
11t² + 7t + 4 = 0
E = mc²
det| 9 4 ; 1 10 | = 86
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
366K
CH₄ + 2O₂ → CO₂ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
176K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 3 6 ; 0 4 | = 12
263K