Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:41Z
11t² + 7t + 4 = 0
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
155K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
ΔS ≥ 0