Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:37Z
7φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
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E = mc²
e^{i\pi} + 1 = 0
∫₀^∞ e^(-n²) dn = √π / 2
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 7 4 ; 4 8 | = 40
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d/dβ [β^2] = 2β^1
det| 7 6 ; 1 8 | = 50
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det| 9 1 ; 5 10 | = 85
det| 6 6 ; 3 7 | = 24
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