Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 00:57Z
12r² + 5r + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
iħ ∂ψ/∂t = Ĥψ
∫₀^∞ e^(-φ²) dφ = √π / 2
63K
11x² + 6x + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
366K
det| 7 4 ; 4 8 | = 40
201K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
176K
2H₂ + O₂ → 2H₂O
PV = nRT
det| 5 9 ; 6 6 | = -24