Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:46Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
326K
det| 5 6 ; 7 6 | = -12
198K
7r² + 8r + 6 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
155K
det| 11 9 ; 0 12 | = 132
63K
∑_{k=1}^{n} k = n(n+1)/2
det| 10 9 ; 3 11 | = 83
det| 7 4 ; 4 8 | = 40
176K
∑_{k=1}^{n} k = n(n+1)/2
319K
∫₀^∞ e^(-φ²) dφ = √π / 2
359K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
263K