Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 00:46Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
479K
7x² + 6x + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
det| 5 6 ; 7 6 | = -12
129K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 4 8 ; 3 5 | = -4
390K
5β² + 9β + 2 = 0
det| 11 9 ; 5 12 | = 87
1K
e^{i\pi} + 1 = 0
det| 7 4 ; 4 8 | = 40
338K
∇²β = 0
E = mc²
10z² + 3z + 2 = 0
det| 4 8 ; 6 5 | = -28