Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 02:06Z
det| 2 2 ; 6 3 | = -6
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 3 3 ; 4 4 | = 0
155K
∑_{k=1}^{n} k = n(n+1)/2
63K
det| 3 1 ; 4 4 | = 8
ΔS ≥ 0
∇ × E = −∂B/∂t
Fe₂O₃ + 3CO → 2Fe + 3CO₂
359K
∫₀^∞ e^(-x²) dx = √π / 2
263K
10φ² + 7φ + 2 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
233K
9r² + 5r + 0 = 0