Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:23Z
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
198K
6φ² + 8φ + 4 = 0
∂φ/∂φ = 1φ
∫₀^∞ e^(-t²) dt = √π / 2
366K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
201K
det| 4 8 ; 1 5 | = 12
det| 5 2 ; 3 6 | = 24
176K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
263K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0