Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:36Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
3β² + 6β + 2 = 0
det| 11 4 ; 5 12 | = 112
276K
det| 3 7 ; 2 4 | = -2
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 7 4 ; 4 8 | = 40
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 11 5 ; 0 12 | = 132
1K
det| 5 9 ; 7 6 | = -33
153K
1x² + 5x + 7 = 0
det| 4 8 ; 1 5 | = 12
∇²ψ = 0