Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:49Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
326K
7r² + 8r + 6 = 0
det| 3 7 ; 2 4 | = -2
63K
∑_{k=1}^{n} k = n(n+1)/2
det| 10 9 ; 3 11 | = 83
∫₀^∞ e^(-φ²) dφ = √π / 2
319K
2ψ² + 6ψ + 0 = 0
det| 2 5 ; 6 3 | = -24
ω = 2πf