Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:50Z
2ψ² + 5ψ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
det| 11 4 ; 5 12 | = 112
276K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
191K
∫₀^∞ e^(-x²) dx = √π / 2
390K
∇²z = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
1K
det| 11 5 ; 0 12 | = 132
153K
N₂ + 3H₂ ⇌ 2NH₃
8t² + 2t + 3 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
416K
F = ma