Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:28Z
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
6φ² + 8φ + 4 = 0
∂φ/∂φ = 1φ
∑_{k=1}^{n} k = n(n+1)/2
366K
det| 4 8 ; 1 5 | = 12
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 4 4 ; 5 5 | = 0
233K
det| 7 2 ; 3 8 | = 50
412K
det| 12 9 ; 2 13 | = 138
\frac{8}{5} \sum_{i=1}^{n} i^{2}