Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 02:28Z
det| 2 2 ; 6 3 | = -6
Fe₂O₃ + 3CO → 2Fe + 3CO₂
CH₄ + 2O₂ → CO₂ + 2H₂O
155K
det| 3 1 ; 4 4 | = 8
ΔS ≥ 0
∇ × E = −∂B/∂t
10φ² + 7φ + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
233K
CH₄ + 2O₂ → CO₂ + 2H₂O
E = mc²