Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 19:34Z
∂r/∂φ = 2r
∫₀^∞ e^(-n²) dn = √π / 2
326K
∫₀^∞ e^(-z²) dz = √π / 2
198K
e^{i\pi} + 1 = 0
det| 7 4 ; 4 8 | = 40
155K
∑_{k=1}^{n} k = n(n+1)/2
63K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-x²) dx = √π / 2
366K
\oint_C \vec{F}\cdot d\vec{r} = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
359K
CH₄ + 2O₂ → CO₂ + 2H₂O
263K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
233K