Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:22Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-z²) dz = √π / 2
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8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-x²) dx = √π / 2
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\lim_{r\to 0} \frac{\sin r}{r} = 1
∫₀^∞ e^(-ψ²) dψ = √π / 2
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det| 11 4 ; 5 12 | = 112
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