Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:17Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 7 6 ; 1 8 | = 50
129K
F = ma
det| 9 4 ; 1 10 | = 86
191K
det| 4 8 ; 3 5 | = -4
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
153K
det| 3 7 ; 2 4 | = -2
473K