Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:09Z
det| 3 3 ; 5 4 | = -3
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
479K
∇²β = 0
det| 1 1 ; 5 2 | = -3
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e^{i\pi} + 1 = 0
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-φ²) dφ = √π / 2
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det| 3 7 ; 2 4 | = -2
det| 9 4 ; 1 10 | = 86
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