Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 20:11Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
234K
12φ² + 9φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
392K
det| 11 9 ; 5 12 | = 87
233K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
4z² + 8z + 0 = 0
det| 5 9 ; 7 6 | = -33
139K
\frac{10}{5} \sum_{i=1}^{n} i^{2}
9ψ² + 7ψ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2