Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:20Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
191K
∫₀^∞ e^(-t²) dt = √π / 2
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 3 3 ; 4 4 | = 0
153K
det| 12 1 ; 1 13 | = 155
∑_{k=1}^{n} k = n(n+1)/2
473K
N₂ + 3H₂ ⇌ 2NH₃