Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:40Z
7φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
E = mc²
e^{i\pi} + 1 = 0
det| 9 4 ; 1 10 | = 86
201K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 4 4 ; 5 5 | = 0
176K
det| 1 4 ; 3 2 | = -10
359K
∑_{k=1}^{n} k = n(n+1)/2
263K