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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 18:38Z

∇²α = 0
ops_3351.mol
iħ ∂ψ/∂t = Ĥψ
326K
mat_6103.dat
N₂ + 3H₂ ⇌ 2NH₃
198K
6φ² + 8φ + 4 = 0
ops_4134.mol
\lim_{α\to 0} \frac{\sin α}{α} = 1
155K
lat_8674.dat
1n² + 7n + 3 = 0
63K
∂φ/∂φ = 1φ
ops_7345.dat
det| 11 5 ; 0 12 | = 132
366K
eq_9391.mol
e^{i\pi} + 1 = 0
201K
det| 4 8 ; 1 5 | = 12
rxn_2615.tex
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
176K
ops_1713.eqn
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
eq_4588.dat
8ψ² + 7ψ + 0 = 0
359K
7φ² + 2φ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0
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