Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:58Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 11 9 ; 5 12 | = 87
1K
∑_{k=1}^{n} k = n(n+1)/2
153K
1x² + 5x + 7 = 0
det| 9 4 ; 1 10 | = 86
473K
det| 11 4 ; 5 12 | = 112
338K
∇²ψ = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃