Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:40Z
∑_{k=1}^{n} k = n(n+1)/2
det| 11 5 ; 0 12 | = 132
479K
8β² + 2β + 0 = 0
det| 7 2 ; 7 8 | = 42
129K
∑_{k=1}^{n} k = n(n+1)/2
det| 5 9 ; 7 6 | = -33
191K
CH₄ + 2O₂ → CO₂ + 2H₂O
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 12 1 ; 1 13 | = 155
N₂ + 3H₂ ⇌ 2NH₃
Fe₂O₃ + 3CO → 2Fe + 3CO₂
416K
det| 5 5 ; 2 6 | = 20