Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 14:36Z
∫₀^∞ e^(-ψ²) dψ = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
479K
e^{i\pi} + 1 = 0
det| 4 4 ; 5 5 | = 0
129K
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\oint_C \vec{F}\cdot d\vec{r} = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
473K
1φ² + 9φ + 2 = 0
∫₀^∞ e^(-β²) dβ = √π / 2
∫₀^∞ e^(-t²) dt = √π / 2
det| 10 2 ; 7 11 | = 96
5n² + 6n + 5 = 0