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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 00:10Z

12r² + 5r + 0 = 0

∇ × E = −∂B/∂t

326K

1β² + 1β + 7 = 0

198K

iħ ∂ψ/∂t = Ĥψ

∑_{k=1}^{n} k = n(n+1)/2

155K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

63K

11x² + 6x + 2 = 0

d/dy [y^11] = 11y^10

366K

det| 7 8 ; 6 8 | = 8

201K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

1θ² + 7θ + 4 = 0

176K

∑_{k=1}^{n} k = n(n+1)/2

319K

2H₂ + O₂ → 2H₂O

CH₄ + 2O₂ → CO₂ + 2H₂O

359K

E = mc²

263K

6φ² + 7φ + 4 = 0

233K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

412K

E = mc²

190K

ω = 2πf

461K

11r² + 2r + 4 = 0

246K

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