Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 18:59Z
6r² + 7r + 2 = 0
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
276K
det| 3 7 ; 1 4 | = 5
det| 7 4 ; 4 8 | = 40
191K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
390K
ΔS ≥ 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
153K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
473K
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
188K
\oint_C \vec{F}\cdot d\vec{r} = 0