Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 19:39Z
∂r/∂φ = 2r
e^{i\pi} + 1 = 0
det| 4 8 ; 3 5 | = -4
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-φ²) dφ = √π / 2
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
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∑_{k=1}^{n} k = n(n+1)/2
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det| 7 4 ; 4 8 | = 40
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