Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:05Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-x²) dx = √π / 2
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12β² + 9β + 3 = 0
∂z/∂n = 8z
\lim_{t\to 0} \frac{\sin t}{t} = 1
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e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\frac{2}{2} \sum_{i=1}^{n} i^{2}
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