Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 06:45Z
det| 4 5 ; 4 5 | = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
276K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
det| 7 4 ; 4 8 | = 40
390K
F = G m₁m₂ / r²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
1K