Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:40Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
∫₀^∞ e^(-n²) dn = √π / 2
129K
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 3 1 ; 7 4 | = 5
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 12 1 ; 1 13 | = 155
∑_{k=1}^{n} k = n(n+1)/2
473K
N₂ + 3H₂ ⇌ 2NH₃
det| 3 7 ; 2 4 | = -2
188K
det| 4 4 ; 5 5 | = 0
416K
det| 5 5 ; 2 6 | = 20