Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:37Z
7φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
198K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
63K
e^{i\pi} + 1 = 0
det| 10 9 ; 0 11 | = 110
201K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 5 6 ; 2 6 | = 18
319K
∫₀^∞ e^(-n²) dn = √π / 2
263K
det| 7 4 ; 4 8 | = 40
233K
det| 5 2 ; 3 6 | = 24
412K