Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:34Z
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
75K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
479K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
F = ma
det| 9 4 ; 1 10 | = 86
390K
10n² + 4n + 5 = 0
det| 11 9 ; 5 12 | = 87
1K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
12x² + 6x + 5 = 0
∫₀^∞ e^(-γ²) dγ = √π / 2
∂ω/∂z = 1ω
det| 6 9 ; 4 7 | = 6