Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:18Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 7 4 ; 4 8 | = 40
479K
3β² + 6β + 2 = 0
det| 5 9 ; 7 6 | = -33
276K
F = ma
det| 5 2 ; 3 6 | = 24
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
1K
det| 1 4 ; 0 2 | = 2
338K
det| 10 9 ; 0 11 | = 110
188K