Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:31Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-t²) dt = √π / 2
75K
3β² + 6β + 2 = 0
det| 3 7 ; 2 4 | = -2
276K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
129K
F = ma
det| 5 6 ; 7 6 | = -12
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
1K
det| 9 4 ; 1 10 | = 86
153K
1x² + 5x + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
188K