Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:28Z
∇ × E = −∂B/∂t
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\frac{8}{9} \sum_{i=1}^{n} i^{2}
det| 3 7 ; 2 4 | = -2
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det| 12 1 ; 4 13 | = 152
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F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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10n² + 4n + 5 = 0
det| 11 4 ; 5 12 | = 112
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det| 9 4 ; 1 10 | = 86
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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