Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 19:27Z
∂r/∂φ = 2r
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
201K
\oint_C \vec{F}\cdot d\vec{r} = 0
\frac{2}{2} \sum_{i=1}^{n} i^{2}
176K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-φ²) dφ = √π / 2
263K
λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
412K
e^{i\pi} + 1 = 0