Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 21:44Z
d/dx [x^11] = 11x^10
∑_{k=1}^{n} k = n(n+1)/2
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4r² + 1r + 1 = 0
∂φ/∂θ = 6φ
det| 4 6 ; 4 5 | = -4
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det| 9 4 ; 1 10 | = 86
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det| 7 6 ; 1 8 | = 50
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∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-φ²) dφ = √π / 2
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