Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:17Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 5 3 ; 2 6 | = 24
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∑_{k=1}^{n} k = n(n+1)/2
129K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
153K
det| 3 7 ; 2 4 | = -2
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