Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:38Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
191K
det| 5 2 ; 3 6 | = 24
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
1K
det| 7 4 ; 4 8 | = 40
153K
det| 12 1 ; 1 13 | = 155
\lim_{t\to 0} \frac{\sin t}{t} = 1
N₂ + 3H₂ ⇌ 2NH₃