Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:47Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
75K
12β² + 9β + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
∂z/∂n = 8z
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
153K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 1 1 ; 5 2 | = -3
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d/dy [y^11] = 11y^10
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det| 7 4 ; 4 8 | = 40
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