Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 06:48Z
det| 4 5 ; 4 5 | = 0
∑_{k=1}^{n} k = n(n+1)/2
479K
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-t²) dt = √π / 2
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\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
F = G m₁m₂ / r²
∫₀^∞ e^(-x²) dx = √π / 2
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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∫₀^∞ e^(-φ²) dφ = √π / 2
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