Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:37Z
det| 3 3 ; 5 4 | = -3
det| 10 2 ; 1 11 | = 108
75K
∑_{k=1}^{n} k = n(n+1)/2
479K
∇²β = 0
det| 4 8 ; 3 5 | = -4
129K
e^{i\pi} + 1 = 0
det| 9 4 ; 1 10 | = 86
191K
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
473K